Question

$2A\leftrightharpoons 4B+C$ concentration of B is found to be increased by $5\times {10}^{-3}mol{L}^{-1}$ in $10$ second . Calculate
i) Rate of Appearance of B
ii) Rate of disappearance of A.

Answer 1

$-\frac{1}{2}\frac{d\left[A\right]}{dt}$ = $+\frac{1}{4}\frac{d\left[B\right]}{dt}$ = $\frac{5\times {10}^{-3}}{10}$

Rate of Appearance of B = $\frac{5\times 4\times {10}^{-3}}{10}$ = $2\times {10}^{-3}mol{L}^{-1}{s}^{-1}$

Rate of Disappearance of A = $\frac{2\times 5\times {10}^{-3}}{10}$ = ${10}^{-3}mol{L}^{-1}{s}^{-1}$