2A n= 3B = 4C find A;B-C

2:4:3

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6:4:3

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5:2:10

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Solution

The correct option is B 6:4:3
Given $2 A = 3 B = 4 C .$

Let $2 A = 3 B = 4 C = K .$

$2 A = K$

$A = \frac{K}{2} - (1)$

$3 B = K, 4 C - k$

$⟹ B = \frac{K}{3}, C = \frac{k}{4} - (2)$

Now,

$A : B : C = \frac{K}{2} : \frac{K}{3} : \frac{K}{4}$

$L C M = 12$

$= \frac{6 K}{12} : \frac{4 K}{12} : \frac{3 K}{12}$

= $6 : 4 : 3.$

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