2ab+3bc+4ba−2cb+3ab+8bc equals
9ab+13bc
9(ab+bc)
7ab+13bc
13(ab+bc)
2ab+3bc+4ba−2cb+3ab+8bc
= 2ab+3bc+4ab−2bc+3ab+8bc
= (2ab+4ab+3ab)+(3bc−2bc+8bc)
= 9ab+9bc
= 9(ab+bc)
Question 57 (h)
Add the following expression:
a2+3ab−bc, b2+3bc−ca and c2+3ca−ab