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Question

2abc(ab+3cab)= _____

A
2a2b2c+6ab2c2
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B
2a2b2c+6a2b2c2
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C
2a2bc+6ab2c
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D
2ab2c+6b2c2
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Solution

The correct option is B 2a2b2c+6a2b2c2
We use distributive law to multiply a monomial and a binomial, as shown below:
(2abc)(ab+3cab)
=(2abc×ab) + (2abc×3cab)
=2a2b2c+6a2b2c2

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