You visited us 1 times! Enjoying our articles? Unlock Full Access!

Oxidation Number Method

2Als+ Fe 2 O ...

Question

$2 A l (s) + {F e}_{2} O_{3} (s) ⟶ {A l}_{2} O_{3} (s) + 2 F e (s)$
According to the equation for the reaction represented above, which of the following statements is true?

2

moles of aluminium are used,

1

mole of iron is produced

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1

mole of aluminium is used,

0.5

{F e}_{2} O_{3}

is consumed

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

1

mole of aluminium is used,

1

{A l}_{2} O_{3}

is consumed

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.5

mole of aluminium is used,

1

{A l}_{2} O_{3}

is consumed

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.5

mole of aluminium is used,

0.5

{F e}_{2} O_{3}

is consumed

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B If $1$ mole of aluminium is used, $0.5$ of ${F e}_{2} O_{3}$ is consumed
$2 A l (s) + F e_{2} O_{3} (s) ⟶ A l_{2} O_{3} (s) + 2 F e (s)$
Since, according to the question for $2$ moles of aluminium, $1$ mole of $F e_{2} O_{3}$ is consumed. Therefore, using the same relation, for $1$ mole of aluminium, $0.5$ moles of $F e_{2} O_{3}$ is consumed.

Suggest Corrections

Similar questions

${F e}_{2} O_{3}$ + $A l$ $\to$ $F e$ + ${A l}_{2} O_{3}$
This is the reaction used in thermite welding process. Calcium can also be used instead of aluminium in this process.

Q. If

\frac{1}{2}

moles of oxygen combine with aluminum to form

A l_{2} O_{3}

, then the weight of aluminum metal used in the reaction is:

2 A l + \frac{3}{2} O_{2} ⟶ {A l}_{2} O_{3}

{F e}_{2} O_{3} + 2 A l \to {A l}_{2} O_{3} + 2 F e

The above reaction is an example of a :

Q. The Gibbs' energy for the decomposition of

{A l}_{2} O_{3}

500^{o} C

is as follows:

\frac{2}{3} {A l}_{2} O_{3} \to \frac{4}{3} A l + O_{2}; Δ_{r} G = + 960 k J {m o l}^{- 1}

The potential difference needed for the electrolytic reduction of aluminium oxide

({A l}_{2} O_{3})

500^{o} C

is at least:

Q. The half mole of oxygen combine with

A l

to form

A l_{2} O_{3}

, the weight of

A l

used in the reaction is:

Join BYJU'S Learning Program

2Al(s)+Fe2O3(s)⟶Al2O3(s)+2Fe(s)According to the equation for the reaction represented above, which of the following statements is true?

The correct option is B If 1 mole of aluminium is used, 0.5 of Fe2O3 is consumed2Al(s)+Fe2O3(s)⟶Al2O3(s)+2Fe(s)Since, according to the question for 2 moles of aluminium, 1 mole of Fe2O3 is consumed. Therefore, using the same relation, for 1 mole of aluminium, 0.5 moles of Fe2O3 is consumed.

$2 A l (s) + {F e}_{2} O_{3} (s) ⟶ {A l}_{2} O_{3} (s) + 2 F e (s)$
According to the equation for the reaction represented above, which of the following statements is true?