Question

2At a certain temperature following reaction have the equilibrium constant as shown below , S+O₂=SO₂ k_c= 5x10^​52 , 2S+3O₂=2SO₃ K_c=10²⁹ What is the equilibrium constant K_cfor the reaction at the same temperature? 2SO₂+ O₂=2SO₃

Answer 1

Dear ​ Hardee Shah,

$$\begin{gathered} Forreaction,S+O_2\to S{O}_2; \\ K{c}_1=\frac{\left[S{O}_2\right]}{\left[S\right]\left[O_2\right]}=5\times {10}^{52} \\ SimilarlyForreaction,2S+3O_2\to 2S{O}_3; \\ K{c}_2=\frac{[S{O}_3{]}^2}{[S{]}^2[O_2{]}^3}={10}^{29} \\ Sofor2S{O}_2+O_2\to 2S{O}_3 \\ K{c}_3=\frac{[S{O}_3{]}^2}{[S{O}_2{]}^2[O_2]}=\frac{K{c}_2}{K{c_1}^2}=\frac{{10}^{29}}{[5\times {10}^{52}{]}^2} \\ K{c}_3=4\times {10}^{-77} \end{gathered}$$

Regards