2Bs - 3 - 2 O 2g - B2O3s- - H - -1273 kj H 2g- 1 - 2 O 2g - H 2Ol - H-286kj H2Ol - H2Og - H - 44 kj 2Bs - 3H2g - B2H6g - H-365 kj B2H6 g- 3O2g B2O3s -3H2Og - H- -

2B(s) + #160; 3 2 O_ 2(g) → B_2O_3(s) #160; #160; Δ H = 1273 kJ Δ H_f^B_2O_3= 1273 kJ (Δ H_f^B=0, Δ H_f^O_2=0) H_ 2(g)+ 1 ...

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2Bs + 3 / 2 O...

Question

$2 B (s) + \frac{3}{2} O_2 (g) \to B_{2} O_{3} (s .)$ $Δ H = - 1273 k j$
$H_2 (g) + \frac{1}{2} O_2 (g) \to H_2 O (l)$ $Δ H = - 286 k j$
$H_{2} O (l) \to H_{2} O (g)$ $Δ H = 44 k j$
$2 B (s) + 3 H_{2} (g) \to B_{2} H_{6} (g)$ $Δ H = 365 k j$
$B_{2} H_{6} (g) + 3 O_{2} (g) B_{2} O_{3} (s) + 3 H_{2} O (g)$ $Δ H = ?$

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B_{2} H_{6 (g)} + 3 O_{2 (g)} \to B_{2} O_{3 (s)} + 3 H_{2} O (g)

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C_{2} H_{2} (g) + \frac{5}{2} O_{2} (g) \to 2 C O_{2} (g) + H_{2} O (l), Δ H = - 1310 k J

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H_{2} (g) + \frac{1}{2} O_{2} (g) \to H_{2} O (l); Δ H = y

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