$2 C a_{3} (P O_{4})_{2} + 6 S i O_{2} + 10 C \to P_{4} +$ __ $C a S i O_{3} + 10 C O$
Which coefficient balances the reaction given above?

2

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4

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5

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6

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Solution

The correct option is D $6$
$2 C a_{3} {(P O_{4})}_{2} + 6 S i O_{2} + 10 C ⟶ P_{4} + x - - C a S i O_{3} + 10 C O$
Balance the columns where $x$ is there.
In $C a$ , $x = 6.$
Oxygen $⟹ 3 x + 10 = 28 3 x = 18 x = 6.$
$S i ⟹ 6 = x$
All the elements are balanced where $x = 6$

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2 C a_{3} (P O_{4})_{2} + 6 S i O_{2} + 10 C \to P_{4} + . . . C a S i O_{3} + 10 C O

2 C a_{3} (P O_{4})_{2} + 6 S i O_{2} + 10 C \to P_{4} + C a S i O_{3} + 10 C O

C a S i O_{3}

2 {C a}_{3} {(P O_{4})}_{2} + 6 S i O_{2} + 10 C \to P_{4} +__C a S i O_{3} + 10 C O

C a_{3} (P O_{4})_{2} + S i O_{2} + C \to C a S i O_{3} + P_{4} + C O

C a O (s) + S i O_{2} (s) \to C a S i O_{3} (s)

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