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Le Chatelier's Principle for Del N Equals to 0

2CaSO4s⇌ 2CaO...

Question

$2 C a S O_{4} (s) ⇌ 2 C a O (s) + 2 S O_{2} (g) + O_{2} (g), Δ H > 0$
Above equilibrium is established by taking a sufficient amount of $C a S O_{4}$ (s) in a closed container at 1600 K. Then which of the following may be the correct option(s)?
(Assume that solid $C a S O_{4}$ is present in the container in each case)

Moles of

C a O (s)

will increase with the increase in temperature

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If the volume of the container is doubled at equilibrium then partial pressure of

S O_{2} (g)

will change at new equilibrium

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If the volume of the container is halved partial pressure of

O_{2}

(g) at new equilibrium will remain same

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If two moles of

H e

gas is added at constant pressure then the moles of

C a O (s)

will increase.

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Solution

The correct options are
A Moles of $C a O (s)$ will increase with the increase in temperature
C If the volume of the container is halved partial pressure of $O_{2}$ (g) at new equilibrium will remain same
For endothermic reaction ( $Δ H > 0$ ) if temperature increases equilibrium shift towards the right. Therefore option $A$ is correct.
For any change in the volume of the container is not going to change the equilibrium pressure at a given temperature if the $C a S O_{4}$ is available. Therefore partial pressure of $S O_{2}$ will not change. $B$ incorrect.
Same reason as for $B$ . Option $C$ is correct.
If any external gas is added to the equilibrium at a constant pressure it will shift towards left. Thus option $D$ is wrong.

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Similar questions

$2 C a S O_{4} (s) ⇌ 2 C a O (s) + 2 S O_{2} (g) + O 2 (g), Δ H > 0$

Above equilibrium is established by taking sufficient amount of $C a S O_{4} (s)$ in a closed container at 1600 K. Then, which of the following may be correct options?
(Assume that solid $C a S O_{4}$ is present in the container in each case).

2 C a S O_{4} (s) ⇌ 2 C a O (s) + 2 S O_{2} (g) + O_{2} (g), Δ H > 0

Above equilibrium is established by taking sufficient amount of CaSO

_{4}

(s) in a closed container at 1600 K. Then which of the following may be correct option(s)?(Assume that solid CaSO

_{4}

is represent in the container in each case)

2 C a S O_{4} (s) ⇌ 2 C a O (s) + 2 S O_{2} (g) + O_{2} (g), Δ H > 0

If the above shown equilibrium is established by taking sufficient amount of

C a S O_{4} (s)

in a closed container at 1600K, then which of the following is(are) correct? (Assume that solid

C a S O_{4}

is present in the container in each case)

Consider the following statements:

(I) An increase in pressure (caused by decrease in volume) at equilibrium results in increase in molar concentration of each gaseous substance involved.

(II) An increase in pressure (caused by decrease in volume) at equilibrium results in increase in no. of moles of each gaseous substance involved.

(III) For the reaction

A (s) ⇌ B (g) + C (g)

at constant temperature, total pressure at equilibrium (of

B (g)

C (g)

) is not affected by changing the volume of container.

(IV)

H_{2} O (l) ⇌ H_{2} O (g)

on temperature increase,

K_{p}

of this reaction is increased.

Tick the correct statement(s)

Q. If

K_{P}

of an equilibrium

C a C O_{3} (s) ⇌ C a O (s) + C O_{2} (g)

is 1.5 atm at

20^{o} C

then the moles of CaO formed if excess

C a C O_{3} (s)

is being placed in a 1 lt of closed container containing

C O_{2}

gas at 0.5 atm pressure at same temperature is:

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2CaSO4(s)⇌2CaO(s)+2SO2(g)+O2(g),ΔH>0Above equilibrium is established by taking a sufficient amount of CaSO4(s) in a closed container at 1600 K. Then which of the following may be the correct option(s)?(Assume that solid CaSO4 is present in the container in each case)