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Question

2CH3COOK+2H2OC2H6+2CO2+2KOH+H2

In the above reaction, the products formed at anode are:

A
C2H6,H2
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B
CO2,H2
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C
C2H6,CO2
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D
H2,KOH
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Solution

The correct option is C C2H6,CO2
The given reaction is a Kolbe's electrolysis reaction for the preparation of alkane.
Reaction occurs at the anode:
2CH3COO.2CH.3+2CO2
2CH.3C2H6
So here one carbon escape as carbon dioxide.

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