$2 C O + O_{2} \to 2 C O_{2}$

$2 H_{2} + O_{2} \to 2 H_{2} O$

If 250 litres of water gas is burnt in air then the volume of steam formed is:

62.5 litres

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250 litres

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125 litres

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375 litres

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Solution

The correct option is A 125 litres
Water-gas A mixture of carbon monoxide ( $C O$ ) and hydrogen ( $H_{2}$ ) produced by passing steam over red-hot coke using the endothermic reaction : $C + H_{2} O \to C O + H_{2}$ .

So, $V_{C O} = V_{H_{2}} = \frac{250}{2} = 125 L$

Now, as per the reaction:

$V_{H_{2}} = V_{H_{2} O (g)} = 125 L$ .

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Similar questions

2 C O + O_{2} \to 2 C O_{2}

2 H_{2} + O_{2} \to 2 H_{2} O

2 C O + O_{2} \to 2 C O_{2}

2 H_{2} + O_{2} \to 2 H_{2} O

C O_{2}

2 C O + O_{2} \to 2 C O_{2};

2 H_{2} + O_{2} \to 2 H_{2} O

O_{2}

2 C O + O_{2} \to 2 C O_{2}; 2 H_{2} + O_{2} \to 2 H_{2} O

Calculate the volume of oxygen at STP required for the complete combustion of 100 litres of carbon monoxide at the same temperature and pressure.

$2 C O + O_{2} ⟶ 2 C O_{2}$

(b) $200 c m^{3}$ of hydrogen and 150 cm of oxygen are mixed and ignited, as per the following reaction,

$2 H_{2} + O_{2} ⟶ 2 H_{2} O$ . What volume of oxygen remains unreacted?

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