$2 {CO}_{2} (g) + 2 H_{2} (g) - - \to 2 CO (g) + 2 H_{2} O (g)$
In this reaction gets oxidised and gets reduced.

{CO}_{2}

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H_{2} O

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H_{2}

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CO

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Solution

The correct options are
A ${CO}_{2}$
C $H_{2}$
In the given reaction, when ${CO}_{2}$ is reacted with hydrogen, it reduces to $CO$ by losing an oxygen atom. Whereas, $H_{2}$ is oxidised as it gains an oxygen atom to form $H_{2} O$ .

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Similar questions

2 {CO}_{2} (g) + 2 H_{2} (g) \to 2 CO (g) + 2 H_{2} O (g)

2 {CO}_{2} (g) + 2 H_{2} (g) - - \to 2 CO (g) + 2 H_{2} O (g)

State, giving reasons, whether the substances printed in bold letters have been oxidised or reduced.

(a) $P b O + C O \to P b + C O_{2}$

(b) $H_{2} S + C l_{2} \to 2 H C l + S$

Z n O + C \to Z n + C O

823

C o O (s) + H_{2} (g) ⇌ C o (s) + H_{2} O (g); K = 67

C o O (s) + C O (g) ⇌ C o (s) + {C O}_{2} (g); K = 490

2 {C O}_{2} (g) + 2 H_{2} (g) ⇌ 2 C O (g) + 2 H_{2} O (g)

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