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Limiting Reagent or Reactant

2Cu2+aq + 5I-...

Question

$2 C u^{2 +} (a q) + 5 I^{-} (a q) \to C u_{2} I_{2} (s) + I_{3}^{-} (a q)$

${I_{3}}^{-} (a q) + 2 {S_{2} O_{3}}^{2 -} (a q) \to {S_{4} O_{6}}^{2 -} (a q) + 3 I^{-} (a q)$

When copper containing alloy of weight $0.3175 g$ is dissolved in an acid and an excess of $K I$ is added, $25$ mL of $0.10 M N a_{2} S_{2} O_{3}$ is required, then Cu present in alloy is_________.

20 %

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40 %

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45 %

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50 %

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Solution

The correct option is D $50 %$
$1$ mole of copper is equivalent to $1$ mole of $N a_{2} S_{2} O_{3}$ .

The number of moles of copper $= \frac{25}{1000} \times 0.10 = 0.0025$

The mass of copper $= 63.5 \times 0.0025 = 0.15875$ g

Mass of an alloy is $0.3175$ g.

The percentage of copper in the alloy is $\frac{0.15875}{0.3175} \times 100 = 50 %$

Hence, the correct option is $(D)$ .

Suggest Corrections

Similar questions

0.3175 g

K I

2 C u^{2 +} (a q) + 5 I^{-} (a q) \to C u_{2} I_{2} (s) + I_{3}^{-} (a q)

{I_{3}}^{-} (a q) + 2 {S_{2} O_{3}}^{2 -} (a q) \to {S_{4} O_{6}}^{2 -} (a q) + 3 I^{-} (a q)

0.3175 g

K I

2 C u^{2 +} (a q) + 5 I^{-} (a q) \to C u_{2} I_{2} (s) + I_{3}^{-} (a q)

{I_{3}}^{-} (a q) + 2 {S_{2} O_{3}}^{2 -} (a q) \to {S_{4} O_{6}}^{2 -} (a q) + 3 I^{-} (a q)

I_{2}

K I_{3}

I_{2}

0.3175 g

K I

2 C u^{2 +} (a q) + 5 I^{-} (a q) \to C u_{2} I_{2} (s) + I_{3}^{-} (a q)

{I_{3}}^{-} (a q) + 2 {S_{2} O_{3}}^{2 -} (a q) \to {S_{4} O_{6}}^{2 -} (a q) + 3 I^{-} (a q)

O

R

0.20

K I

C u^{2 +}

I^{-}

C u^{2 +} (a q) + I^{-} (a q) \to C u I (s) + I_{3}^{-} (a q)

I_{3}^{-} (a q) + S_{2} O_{3}^{2 -} (a q) \to S_{4} O_{6}^{2 -} (a q) + 3 I^{-} (a q)

20

0.1 M

N a_{2} S_{2} O_{3}

C u

2 C u^{2 +} (a q) + 4 I^{-} (a q) ⇌ 2 C u I (s) + I_{2} (a q)

24.5 c m^{3}

0.100 m o l e d m^{- 3}

2 S_{2} {O_{3}}^{2 -} (a q) + I_{2} (a q) \to 2 I^{-} (a q) + S_{4} {O_{6}}^{2 -} (a q)

[A t o m i c m a s s o f c o p p e r = 63.5]

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