The correct option is D 8e^ 1 (2d^2e^ 1)^3 ( d^3e )^2 ⇒2^3× d^6e^ 3× d^ 6e^ 2 #160; ⇒ 2^3e^ 1=8e^ 1 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Exponents with Like Bases

2d2e-13 × d3e...

Question

$(2 d^{2} e^{- 1})^{3} \times (\frac{d^{3}}{e})^{- 2} =$ __.

8 e^{- 2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

8 e^{- 3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

8 e^{- 1}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

8 e^{- 4}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is D $8 e^{- 1}$
$(2 d^{2} e^{- 1})^{3} {(\frac{d^{3}}{e})}^{2}$
$\Rightarrow \frac{2^{3} \times d^{6} e^{- 3} \times d^{- 6}}{e^{- 2}}$
$\Rightarrow 2^{3} e^{- 1} = 8 e^{- 1}$

Suggest Corrections

Similar questions

lim x \to 0 \frac{(1 + a^{3}) + 8 e^{1 / x}}{1 + (1 - b^{3}) e^{1 / x}} = 2

lim x \to 0 \frac{(1 + a^{3}) + 8 e^{1 / x}}{1 + (1 - b^{3}) e^{1 / x}} = 2

S (x) = \int \frac{d x}{e^{x} + 8 e^{- x} + 4 e^{- 3 x}}, R (x) = \int \frac{d x}{e^{3 x} + 8 e^{x} + 4 e^{- x}}

M (x) = S (x) - 2 R (x) .

M (x) = \frac{1}{2} t a n^{- 1} (f (x)) + c

The value of x $^{1 / 2}$ .y $^{- 1}$ . z $^{2 / 3}$ , when x = 9 , y = 3 and z = 8 is

Join BYJU'S Learning Program