$2 F e_{2} (S O_{4})_{3} + 3 K_{4} [F e (C N)_{6}] ⟶ X + 6 K_{2} S O_{4}$

The reason of color of $X,$ if ________.

d-d transition

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charge transfer

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colorless compound

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Filling of the

t_{2 g}

orbitals

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Solution

The correct option is B charge transfer
Here X is
$F e_{4} [F e (C N)_{6}]_{3}$
+2
$F e^{+ 2} = d^{6}$ configuration, low spin complex due to strong ligand & pairing of electron happens.
Also, here $F e^{+ 2} = d^{2} s p^{3}$ hybridization so two d-orbitals involved.
Also, color is due to charge transfer complex.

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2 F e_{2} (S O_{4})_{3} + 3 K_{4} [F e (C N)_{6}] ⟶ X + 6 K_{2} S O_{4}

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