$2 F e_{2} (S O_{4})_{3} + 3 K_{4} [F e (C N)_{6}] ⟶ X + 6 K_{2} S O_{4}$
How many d-orbitals are involved in hybridization?

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Solution

The correct option is A $2$
Here X is
$F e_{4} [F e (C N)_{6}]_{3}$
+2
$F e^{+ 2} = d^{6}$ configuration, low spin complex due to strong ligand & pairing of electron happens.
Also, here $F e^{+ 2} = d^{2} s p^{3}$ hybridization so two d-orbitals involved.

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