2Fe - 3-2 O2 - Fe2O3 - x kJ - mol 2Fe - O2 - 2FeO- y kJ - mol The - H to form one mole of Fe3O4 from Fe and O2 is -

The correct option is B 2x + y/2 2x + y = 2 moles of Fe_3O_4 (Since #160;FeO + Fe_2O_3 → #160;Fe_3O_4 ) ∴ 1 mole of Fe_3O_4 = ...

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Volume of Gases and Number of Moles

2Fe + 3/2 O2 ...

Question

$2 F e + \frac{3}{2} O_{2} \to F e_{2} O_{3}; x k J / m o l$

$2 F e + O_{2} \to 2 F e O; y k J / m o l$
The $Δ H$ to form one mole of $F e_{3} O_{4}$ from Fe and $O_{2}$ is :

\frac{x}{2} + y

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\frac{2 x + y}{2}

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\frac{2 x - y}{2}

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\frac{y - 2 x}{2}

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Solution

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Similar questions

C (s) + O_{2} (g) \to C O_{2} (g); Δ H^{\circ} = - x k J

2 C O (g) + O_{2} (g) \to 2 C O_{2} (g); Δ H^{\circ} = - y k J

O_{2} \to S O_{3}

S O_{2} + 1 / 2 O_{2} \to S O_{3}

S O_{2}

S + \frac{3}{2} O_{2} \to {S O}_{3} + 2 x

{S O}_{2} + \frac{1}{2} O_{2} \to {S O}_{3} + y

{S O}_{2}

F e_{2} O_{3 (s)} + 3 C O_{(g)} \to 2 F e (s) + 3 C O_{2 (g)}

Δ H = - 26.8 k J

F e O_{(s)} + C O_{(g)} \to F e_{(s)} + C O_{2 (g)} Δ H = - 16.5 k J

Δ H

F e_{2} O_{3 (s)} + C O_{(g)} \to 2 F e O_{(s)} + C O_{2 (g)}

\frac{3 y (x - y) - 2 x (y - 2 x)}{7 x (x - y) - 3 (x^{2} {- y}^{2})}

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