MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Relation between Kp and Kc

2g molecules ...

Question

$2 g$ molecules of $P C l_{5}$ were heated in a pot of $3 L$ . $50$ $P C l_{5}$ dissociated at equilibrium . calculate the equilibrium constant of the reaction.

Open in App

Solution

$P C l_{5} ⇌ P C l_{3} + C l_{2}$
$1$ mole $0$ $0$ Starting
$0.5$ $0.5$ $0.5$ At equilibrium
Pressure at equilibrium= $2 \times \frac{1.5}{1} = 3 a t m$
Partial pressure $P_{P C l_{5}} = 3 \times \frac{0.5}{1.5} = 1 a t m, P_{P C l_{3}} = 3 \times \frac{0.5}{1.5} = 1$
$P_{C l_{2}} = 3 \times \frac{2.5}{1.5} = 1 a t m$
$K_{P} = \frac{P_{P C l_{3}} P_{C l_{2}}}{P_{P C l_{5}}} = \frac{1 \times 1}{1} = 1 a t m$ .

Suggest Corrections

thumbs-up

0

Similar questions

P C l_{5}

327^{o} C

in a closed 2 L vessel and when equilibrium was achieved,

P C l_{5}

was found to be 40% dissociated into

P C l_{3}

C l_{2} .

Calculate the equilibrium constant

(K_{C})

for the reaction

2

P C l_{5}

were heated in a closed vessel of

2

liter capacity. At equilibrium,

40 %

P C l_{5}

dissociated into

P C l_{3}

C l_{2}

The value of equilibrium constant is:

2 mol

P C l_{5}

327^{o} C

2 L

vessel and when equilibrium was achieved,

P C l_{5}

was found to be

40 %

dissociated into

P C l_{3}

C l_{2} .

What will be the equilibrium constant

(K_{C})

for the reaction:

2

P C l_{5}

were heated in a closed vessel of 2 litre capacity. At equilibrium,

40 %

P C l_{5}

is dissociated into

P C l_{3}

C l_{2}

. The value of equilibrium constant is-

P C l_{5},

were heated in a closed vessel of 2 litre capacity. At equilibrium, 40% of

P C l_{5}

is dissociated into

P C l_{3} a n d C l_{2} .

The value of equilibrium constant is

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Equilibrium Constants

CHEMISTRY

Watch in App

explore_more_icon

Explore more

Relation between Kp and Kc

Standard XII Chemistry

Join BYJU'S Learning Program

CrossIcon