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Arrhenius Acid

2g of NaOH an...

Question

$2 g$ of NaOH and $4.9 g$ of $H_{2} S O_{4}$ are mixed and volume is made $1$ litre. The normality of the resulting solution will be:

1 N

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0.05 N

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0.5 N

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0.1 N

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Solution

The correct option is A $0.05 N$
$N = \frac{N u m b e r o f g r a m e q u i v a l e n t s o f s o l u t e}{V o l u m e o f s o l u t i o n i n L}$
Number of gram equivalent of solute $= \frac{g i v e n m a s s}{e q u i v a l e n t w e i g h t}$
Equivalent weight $= \frac{M o l a r m a s s}{n - f a c t o r O R V a l e n c y f a c t o r}$
For $N a O H, E q u i v a l e n t w e i g h t = \frac{40}{1}$
Number of gram equivalent of solute i.e $N a O H = \frac{2}{40} = \frac{1}{20}$
$N = \frac{1 / 20}{1}$
$N = \frac{1}{20} = 0.05 N$

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