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Byju's Answer
Standard XII
Physics
Law of Radioactivity
2gm of radio ...
Question
2
g
m
of radio active element undergoes
3.7
×
10
8
disintegrations per second. Its curie value is
A
2
g
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B
0.02
g
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C
200
g
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D
3700
g
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Solution
The correct option is
C
200
g
R
=
λ
N
=
d
N
d
t
,
1
G
=
3.7
×
10
10
decay/sec
R
=
3.7
×
10
8
decay/sec
R
=
(
0.01
)
G
0.01
=
2
λ
⇒
λ
=
200
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0
Similar questions
Q.
1
g
of radio active substance disintegrates at the rate of
3.7
×
10
10
disintegrations per second. The atomic mass of the substance is
226
. Calculate its means life.
Q.
Show that the mass of radium
(
88
R
a
226
)
with an activity of
1
curie is almost
1
gram
[
T
1
2
=
1600
years].
[
1
curie
=
3.7
×
10
10
disintegrations per second].
Q.
The curie was originally intended to be the activity of one gram of radium-226. The actual weight of radium which is equal to one curie is (in gm)
T
50
(Radius-226) = 1620 years
One curie =
3.7
×
10
10
disintegrations (of atoms) per second (dps)
One year =
3.154
×
10
7
seconds
Q.
The activity of a radioactive nuclide (X
100
) is
6.023
curie. If its disintegration constant is
3.7
x
10
4
sec
−
1
, then the mass of X is
Q.
A small quantity of solution containing
24
Na radionuclide (half life 15 hours) of activity 1.0 microcuric is injected into the blood of a person.A sample of the blood of volume
1
c
m
3
taken after 5 hours shows an activity of 296 disintegrations per minute.Determine the total volume of blood in litre in the body of the person.Assume that the radioactivity solution mixes uniformly in the blood of the person.
(
1
C
u
r
i
e
=
3.7
∗
10
10
disintegrations per second).
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