$2 H_{2 (g)} + O_{2 (g)} \to 2 H_{2} O_{(l)}$
$△ H^{+} = - 572 k J$
Statement I: Above given reaction is exothermic.
Because
Statement II: The total enthalpy of the products in this reaction is less than that of the reactants

true, true correct explanation

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true, true not correct explanation

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true, false

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false, true

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false, false

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Solution

The correct option is B true, true correct explanation
Statement I: Above given reaction is exothermic.
Statement II: The total enthalpy of the products in this reaction is less than that of the reactants.
This is confirmed by negative value of the enthalpy change.
Hence, both statements are correct.

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Similar questions

Q. In an exothermic reaction, the total enthalpy of reactant is greater than that of products.

State whether the statement is True or False

Q. Statement I: Above reaction is exothermic.
Because
Statement II: Energy difference B is greater than energy difference A.

Q. Pick the correct option given the following statements:
Statement I Nuclide

_{13}^{30} A l

is less stable than

_{20}^{40} C a

Statement II Nuclides having odd number of protons and neutrons are generally unstable.

Q. Question 17
In which of the following chemical equations, the abbreviations represent the correct states of the reactants and products involved at reaction temperature?

(a)

2 H_{2} (l) + O_{2} (l) \to 2 H_{2} O(g)

(b)

2 H_{2} (g) + O_{2} (l) \to 2 H_{2} O(l)

(c)

2 H_{2} (g) + O_{2} (g) \to 2 H_{2} O(l)

(d)

2 H_{2} (g) + O_{2} (g) \to 2 H_{2} O(g)

Statement - I: $M g^{2 +} a n d A l^{3 +}$ are isoelectronic but ionic radius $A l^{3 +}$ is less than that of $M g^{2 +}$ .
Statement - II: The effective nuclear charge on the outer-shell electrons in $A l^{3 +}$ is more than that in $M g^{2 +}$

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2H2(g)+O2(g)→2H2O(l)△H+=−572kJStatement I: Above given reaction is exothermic.BecauseStatement II: The total enthalpy of the products in this reaction is less than that of the reactants

The correct option is B true, true correct explanationStatement I: Above given reaction is exothermic.Statement II: The total enthalpy of the products in this reaction is less than that of the reactants. This is confirmed by negative value of the enthalpy change.Hence, both statements are correct.

$2 H_{2 (g)} + O_{2 (g)} \to 2 H_{2} O_{(l)}$
$△ H^{+} = - 572 k J$
Statement I: Above given reaction is exothermic.
Because
Statement II: The total enthalpy of the products in this reaction is less than that of the reactants