$2 H_{2} O_{2} ⟶ 2 H_{2} O + O_{2}$
In this reaction:

oxygen is oxidised

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oxygen is reduced

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oxygen is neither oxidized nor reduced

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oxygen is both oxidized and reduced

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Solution

The correct option is A oxygen is reduced
The reaction is-
$2 H_{2} O_{2} \to {2 H}_{2} O + O_{2}$
In $H_{2} O_{2}$ oxidation state of $O$ is -1
In $H_{2} O$ oxidation state of $O$ is -2
In $O_{2}$ oxidation state of $O$ is 0.
In the given reaction oxidation state of oxygen is decreases.
So oxygen is reduced
The correct option is $B$ .

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