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Characteristics of Chemical Reaction

2H2O2aq⟶2H2Ol...

Question

$2 H_{2} O_{2} (a q) ⟶ 2 H_{2} O (l) + O_{2} (g)$ ,

Hydrogen peroxide in aqueous solution decomposes on warming to give oxygen according to the given equation under conditions where one mole of gas occupies $24 d m^{3}$ . $100 c m^{3}$ of $x M$ solution of $H_{2} O_{2}$ produces $3 d m^{3}$ of $O_{2}$ .
Thus, $x$ is :

2.5

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0.5

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0.25

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Solution

The correct option is A 2.5
$2 H_{2} O_{2} (a q) \to 2 H_{2} O (l) + O_{2} (g)$

From the above equation 2 moles of $H_{2} O_{2}$ produces 1 mole of $O_{2}$

Given that 100 ml (1 cc = 1 ml) of X M solution of $H_{2} O_{2}$ produces 3 dm³ of $O_{2}$
Also 1 mole of $O_{2}$ occupies 24 dm³ of space

Thus, 1/8 moles of $O_{2}$ will occupy 3 dm³ of space

Therefore the moles of $H_{2} O_{2} = 2 \times 1 / 8 = 1 / 4 = 0.25$

$∵$ 100 mL moles of $H_{2} O_{2}$ = 0.25

$∴$ 1000 mL moles of $H_{2} O_{2}$ = 2.5

Therefore, the molarity of $H_{2} O_{2}$ = 2.5 M

Hence, $x = 2.5$

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