$2 H_{2} S (g) + 3 O_{2} (g) \to 2 S O_{2} (g) + 2 H_{2} O (g) +$ heat
$F e_{2} O_{3} (s) + 3 C O (g) \to 2 F e (s) + 3 C O_{2} (g)$
According to the above reaction , 3 moles of $F e_{2} O_{3}$ are allowed react with 56 grams of CO so, find the approximately moles of iron produced ?

0.7

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1.3

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2

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2.7

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6

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Solution

The correct option is B $1.3$
CO molar mass is 28 g/mol. 56 g of CO corresponds to $\frac{56}{28} = 2$ moles.
3 moles of $F e_{2} O_{3}$ will react with $3 \times 3 = 9$ moles of CO however only 2 moles of CO are present. Hence, the CO is the limiting reagent.
3 moles of CO produces 2 moles of Fe.
Hence, 2 moles of CO will produce $\frac{2 \times 2}{3} = 1.3$ moles of Fe.

Suggest Corrections

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