$2 H_{2} S (g) + 3 O_{2} (g) \to 2 S O_{2} (g) + 2 H_{2} O (g) +$ heat
For the given reaction, the equilibrium concentration of $S O_{2} (g)$ can be increased by which of the following ?

Adding neon gas

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Increasing the temperature

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Adding a catalyst

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Increasing the concentration of

H_{2} O (g)

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Increasing the concentration of

O_{2} (g)

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Solution

The correct option is C Increasing the concentration of $O_{2} (g)$
According to Le Chatelier's principle, a change in pressure, temperature or concentration of the reactant will shift the reaction in a direction so as to counteract the effect of the change. As per the reaction, increasing the concentration of $O_{2}$ will shift the direction of equilibrium to the product side thus consuming more oxygen and forming more $S O_{2}$ . Hence, E is the correct answer

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Similar questions

2 H_{2} S (g) + 3 O_{2} (g) \to 2 S O_{2} (g) + 2 H_{2} O (g) +

K_{e q}

2 H_{2} S (g) + 3 O_{2} (g) \to 2 S O_{2} (g) + 2 H_{2} O (g) +

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C O_{2}

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C O

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