2KMnO $_{4}$ + 3Na $_{2}$ SO $_{3}$ + H $_{2}$ O $\to$ 2MnO $_{2}$ + 3Na $_{2}$ SO $_{4}$ + 2KOH
Reducing agent in the above reaction shown is :

^{+}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

MnO

_{4}^{-}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

_{3}^{2 -}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

^{+}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C SO $_{3}^{2 -}$
Reducing agent in the above reaction shown is $S O_{3}^{2 -}$ ion as S atom itself is oxidized.
The oxidation number of S increases from +4 (in $S O_{3}^{2 -}$ ) to +6 (in $S O_{4}^{2 -}$ ).

Suggest Corrections

Similar questions

Identify the reducing agent in the following redox reaction:

$5 S O_{3}^{2 -} + 2 M n O_{4}^{-} + 6 H^{+} \to 5 S O_{4}^{2 -} + 2 M n^{2 +} + 3 H_{2} O$

Complete the following reaction: $N a_{2} C O_{3} + H_{2} S O_{4} \to$ ___?

Complete the following reaction:

${Na}_{2} {CO}_{3} (s) + H_{2} {SO}_{4} (aq) \to ?$

N a_{2} C O_{3} + H_{2} S O_{4} \to

K_{2} {C r}_{2} O_{7} + K I + H_{2} {S O}_{4} \to K_{2} {S O}_{4} + {C r}_{2} {({S O}_{4})}_{3} + I_{2} + H_{2} O

K M n O_{4} + {N a}_{2} {S O}_{3} \to M n O_{2} + {N a}_{2} {S O}_{4} + K O H

C u + H {N O}_{3} \to C u {({N O}_{3})}_{2} + {N O}_{2} + H_{2} O

K M {n O}_{4} + H_{2} C_{2} O_{4} + H_{2} {S O}_{4} \to K_{2} {S O}_{4} + {M n S O}_{4} + {C O}_{2} + H_{2} O

Join BYJU'S Learning Program