$2 L$ of an ideal gas at a pressure of $10$ atm expands isothermally into a vacuum until its total volume is $10 L$ . How much work is done in the expansion?

8 L-atm

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16.1 L-atm

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24.0 L-atm

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no work done

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Solution

The correct option is D no work done
The given case is in a vacuum where there is no pressure associating with an ideal gas.

So, $P_{e x} = 0$ .

$W = - P_{e x} (10 - 2) = 0 \times 8 = 0$ .

No work is done.

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2L of an ideal gas at a pressure of 10 atm expands isothermally into a vacuum until its total volume is 10L. How much work is done in the expansion?

The correct option is D no work doneThe given case is in a vacuum where there is no pressure associating with an ideal gas. So, Pex=0.W=−Pex(10−2)=0×8=0. No work is done.

$2 L$ of an ideal gas at a pressure of $10$ atm expands isothermally into a vacuum until its total volume is $10 L$ . How much work is done in the expansion?

The correct option is D no work done
The given case is in a vacuum where there is no pressure associating with an ideal gas.

So, $P_{e x} = 0$ .

$W = - P_{e x} (10 - 2) = 0 \times 8 = 0$ .

No work is done.