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Stoichiometry

2LiOH+C O 2 →...

Question

$2 L i O H + C O_{2} \to {L i}_{2} {C O}_{3} + H_{2} O$
If $0.24 g$ of $L i O H$ is to react fully with ${C O}_{2}$ , what volume of $C O_{2}$ would required?
Assume STP conditions.

90 m L

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80 m L

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100 m L

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120 m L

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Solution

The correct option is D $120 m L$
$2 L i O H + C O_{2} \to L i_{2} C O_{3} + H_{2} O$
$2 m o l e s$ of $L i O H$ react fully with $22.4 L i t r e s$ of $C O_{2}$ at STP.
Molar mass of $L i O H = 7 + 16 + 1 = 24 g$

So, $48 g$ $L i O H \to$ $22400 m L C O_{2}$
$0.24 g$ $L i O H \to$ $(x) C O_{2}$
$\Rightarrow x \times 48 = 0.24 \times 22400$
$\Rightarrow x = 112 m L \approx 120 m L$

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