Given 2m^2 3m+10m 5 Now (2m^2 3m+10) can be written after dividing by (m 5) as #160; (2m^2 3m+10)=((2m+7)×(m 5))+45 so 45 is remainder an ...

309

You visited us 309 times! Enjoying our articles? Unlock Full Access!

Theorems for Differentiability

2m2-3m+10÷ m-...

Question

$(2 m^{2} - 3 m + 10) \div (m - 5)$ .

Open in App

Solution

To evaluate:
$\frac{2 m^{2} - 3 m + 10}{m - 5}$
Lets do the division by using long division method,

Now $(2 m^{2} - 3 m + 10)$ can be written after dividing by $(m - 5)$ as
$(2 m^{2} - 3 m + 10) = ((2 m + 7) \times (m - 5)) + 45$
So, $45$ is Remainder and $(2 m + 7)$ is Quotient

Suggest Corrections

Similar questions

\frac{(2 m^{2} - 3 m - 10)}{(m - 5)}

2 m^{2} - 3 m + 10 = 0

m - 5

2 m^{2} - 3 m + 10

-

-

-

-

2 m^{3} + 3 m - 2 m^{2} - 3

Join BYJU'S Learning Program