$2 M g + O_{2} \to 2 M g O$ , Calculate how much oxygen (in grams) required to combust $10$ moles of Magnesium from the given equation.

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Solution

$2 M g + O_{2} \to 2 M g O$

1 mole of $O_{2}$ is required for 2 Moles of $M g$
5 Moles of $O_{2}$ is required for 10 Moles of $M g$

So , $32 \times 5$ g of $O_{2}$ is required = 160 g
160 g of $O_{2}$ is required to combust 10 Moles of Mg

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