Question

2mol of $A_2$ gas in one flask (1 lit volume) is allowed to react with 4 mol of $B_2$ gas presence in another flask (3 lit volume) as $A_2\left(g\right)+B_2\left(g\right)\rightleftharpoons 2AB\left(g\right);K_c=4at{27}^{o}C.$ What is the concentration of AB when equilibrium is established?

• A. 1.33 M
• B. 2.66 M
• C. 0.66 M
• D. 0.33 M

Answer 1

The correct option is C 0.66 M

The reaction is,

$\begin{array}{cccccc}& A_2\left(g\right)& +& B_2\left(g\right)& \rightleftharpoons & 2AB\left(g\right)\\ Molesateqm& 2-x& & 4-x& & 2x\end{array}$

$K_c=\frac{4x^2}{(2-x)(4-x)}$

putting values, we get;
$\Rightarrow x=\frac{32}{24}=1.33mole$

Here total volume=$1l+3l=4l$
Concentration of AB=$\frac{2x}{volume}$
=$\frac{2x}{4}$
Putting the values,
Concentration of AB = $0.66M$