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Question
2n=16 is a primary spermatocyte, which is in metaphase of first meiotic division. What shall be the total number of chromatids in each of the secondary spermatocyte?
2n=16 is a primary spermatocyte, which is in metaphase of first meiotic division. What shall be the total number of chromatids in each of the secondary spermatocyte?
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Solution
The correct option is C 16
In spermatogenesis, primary spermatocyte undergoes meiosis-I and as a result of which two haploid secondary spermatocytes are formed. Thus for the given case, secondary spermatocyte possesses 8 chromosomes, i.e., 𝑛=8 and 16 chromatids because each chromosome has two chromatids.
In spermatogenesis, primary spermatocyte undergoes meiosis-I and as a result of which two haploid secondary spermatocytes are formed. Thus for the given case, secondary spermatocyte possesses 8 chromosomes, i.e., 𝑛=8 and 16 chromatids because each chromosome has two chromatids.
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