Question

$2N_2{O}_5\to 4N{O}_2+O_2$
If $-\frac{d\left[N_2{O}_5\right]}{dt}=k_1\left[N_2{O}_5\right]$
$\frac{d\left[N{O}_2\right]}{dt}=k_2\left[N_2{O}_5\right]$
$\frac{d\left[O_2\right]}{dt}=k_3\left[N_2{O}_5\right]$
What is the relation between $k_1,k_{2}and{k}_3$ ?

• A. $k_1=k_2=k_3$
• B. $2k_1=k_2=4k_3$
• C. $2k_1=4k_2=k_3$
• D. None

Answer 1

The correct option is B $2k_1=k_2=4k_3$

As we know,
for a reaction:
$2N_2{O}_5\to 4N{O}_2+O_2$
$-\frac{1}{2}\frac{d\left[N_2{O}_5\right]}{dt}=\frac{1}{4}\frac{d\left[N{O}_2\right]}{dt}=\frac{d\left[O_2\right]}{dt}$
So
$2k_1=k_2=4k_3$