2n-n2 when n - N such that

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Importance of Brackets

2n>n2 when n ...

Question

2ⁿ > n² when n Є N such that

n < 5

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n > 3

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n > 2

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n ≥ 5

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Solution

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n^{2}

n \times n

1^{2} + {2.2}^{2} + 3^{2} + {2.4}^{2} + 5^{2} + {2.6}^{2} + \dots . i s \frac{n}{2} (n + 1)^{2}

{lim}_{n \to \infty} (\frac{n}{n^{2}} + \frac{n}{n^{2} + 1} + \frac{n}{n^{2} + 2^{2}} + . . . . . . + \frac{n}{2 n^{2} - 2 n + 1})

n^{2} < 2^{n} \forall n \geq 5

{(| n - -)}^{2} > n^{n}

2.4.6...2 n < {(n + 1)}^{n}

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