The molecularity and order of the given reaction, are respectively:
A
One and one
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B
Two and two
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C
Three and three
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D
Two and three
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Solution
The correct option is D Three and three The reaction is trimolecular, that is, three species are involved. The probability of the three species colliding with each other simultaneously with the correct energy and the correct orientation in a single step is very small. Thus, the actual mechanism for the oxidation of NO with O2 involves the following two steps :
An initial dimerisation in an equilibrium reaction :
2NO(g)↔N2O2(g) ...(i)
It is followed by reaction of the dimer with the oxygen.
N2O2(g)+O2(g)→2NO2(g) ...(ii)
The mechanism has the same stoichiometry as the overall reaction. Step 1 is reversible and thus equilibrium is reached quickly in it. While, step 2 is the rate determinant step, as it is very slow. Thus, the overall molecularity of the reaction is two. The reaction between two molecules of NO and one molecule of O2 gives one molecule of NO2. Thus, the order fo reaction is three. This is one of only five homogeneous gas reactions known to be third order.