$2 N a (s) + 2 H_{2} O \to 2 N a^{+} (a q) + 2 O H^{-} (a q) + H_{2} (g)$
Match the oxidation number of the following atoms in various species.

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Solution

The given reaction is as follows:
$2 N a (s) + 2 H_{2} O \to 2 N a^{+} (a q) + 2 O H^{-} (a q) + H_{2} (g)$

$\begin{matrix} 2 N a (s) ↑ 0 \end{matrix} + \begin{matrix} 2 H_{2} O ↑ + 1 \end{matrix} \begin{matrix} (l) ↑ - 2 \end{matrix} \to \begin{matrix} 2 N a^{+} (a q)) ↑ + 1 \end{matrix} + \begin{matrix} 2 O H^{-} ↑ - 2 \end{matrix} \begin{matrix} (a q)) ↑ + 1 \end{matrix} + \begin{matrix} H_{2} (g) ↑ 0 \end{matrix}$

Hence, the oxidation number of $N a$ is $0$ , $H$ in $H_{2} O$ is $+ 1$ , $O$ in $O H^{-}$ is $- 2$ and $N a$ in $N a^{+}$ is $+ 1$ .

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