$2 N a C l + H_{2} S O_{4} ⟶ N a_{2} S O_{4} + H C l$ . This reaction occurs when the temperature is :

200^{\circ} C

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more than

200^{\circ} C

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less than

200^{\circ} C

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None of the above

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Solution

The correct option is A more than $200^{\circ} C$
If the reaction is carried out at temperature less then $200^{\circ} C$ than instead of $N a_{2} S O_{4}$ we will get $N a H S O_{4}$ .
$N a C l + H_{2} {S O}_{4} < 200^{\circ} C - --- \to N a H {S O}_{4} + H C l$

Hence reaction carry out at more than $200^{0} C$ .

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Similar questions

N a C I + H_{2} S O_{4} < 200 \circ C - ---- \to

N a C I + H_{2} S O_{4} > 200 \circ C - ---- \to

N H_{3} + H C l \to

N a_{2} C O_{3} + H C l \to

C u (N O_{3})_{2} + H C l \to

200

Life-time (in days)	Less than 50	Less than 100	Less than 150	Less than 200	Less than 250	Less than 300
Number of bulbs	7	21	52	79	91	100

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