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Byju's Answer
Standard XII
Chemistry
Anomalous Behavior of Lithium Halogens
2NaIO3+5NaHSO...
Question
2
N
a
I
O
3
+
5
N
a
H
S
O
3
→
2
N
a
H
S
O
4
+
2
N
a
2
S
O
4
+
H
2
O
+
I
2
if the given reaction is used for the preparation of iodine gas then how much
N
a
H
S
O
3
is required to produce
381
g of
I
2
?
A
156.0
g
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B
390.0
g
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C
520.0
g
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D
780.0
g
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Solution
The correct option is
D
780.0
g
The molar masse of
N
a
H
S
O
3
is 104 g/mol and iodine is 253.8 g/mol respectively.
From the balanced chemical equation, it can be seen that 5 moles of
N
a
H
S
O
3
give 1 mole of iodine.
Hence,
5
×
104
=
520
g of
N
a
H
S
O
3
will give 253.8 g of iodine.
Hence, 381 g of iodine will be prepared by
520
253.8
×
381
=
780
g of
N
a
H
S
O
3
Hence, the option
(
D
)
is correct.
Suggest Corrections
0
Similar questions
Q.
What mass of
H
N
O
3
is needed to convert 5 g of iodine into iodic acid according to the reaction?
I
2
+
H
N
O
3
→
H
P
O
3
+
N
O
2
+
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2
O
Q.
How much amount of
C
u
S
O
4
.
5
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required for liberation of
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when titrated with
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?
Q.
Calculate the mass of
K
2
C
r
2
O
7
required to produce
254
g
I
2
from
K
I
solution.
K
2
C
r
2
O
7
+
K
I
→
C
r
3
+
+
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2
(Molar mass of
K
2
C
r
2
O
7
is
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g
m
o
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−
1
)
Q.
How many grams of hydrogen gas is required to produce 4.8 mol of ammonia on a reaction with an excess of nitrogen?
Q.
In the following sequence of reactions:
C
a
O
C
l
2
+
H
2
O
⟶
C
a
(
O
H
)
2
+
C
l
2
2
K
I
+
C
l
2
⟶
2
K
C
l
+
I
2
I
2
+
2
N
a
2
S
2
O
3
⟶
N
a
2
S
4
O
6
+
2
N
a
I
Calculate moles of
N
a
2
S
2
O
3
required for complete reduction of
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2
obtained from
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a
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l
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sample (
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%
purity).
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