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Solubility Product

2NOBrg⇌ 2NOg+...

Question

$2 N O B r (g) ⇌ 2 N O (g) + B r_{2} (g)$ . If nitrosyl bromide $(N O B r)$ is $40 %$ dissociated at certain temp. and a total pressure of $0.30$ atm. $K_{p}$ for the reaction $2 N O (g) + B r_{2} (g) ⇌ 2 N O B r (g)$ is:

45

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25

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0.025

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0.25

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Solution

The correct option is C $0.025$
$2 N O B r ⇌ 2 N O + {B r}_{2} 200 2 - 2 (0.4) 2 (0.4) 0.4 1.2 0.8 0.4$
Therefore,
$n_{T} = 2.4$
hence,
$K_{p} = \frac{p_{N O}^{2} . p_{B r_{2}}}{p_{N O B r}^{2}}$
$K_{p} = \frac{(\frac{0.8}{2.4} \times 3)^{2} . (\frac{0.4}{2.4} \times 0.3)}{(\frac{1.2}{2.4} \times 0.3)^{2}}$
$K_{p} = 0.025$

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