Using First Out Inside Last (FOIL) technique, ⇒(2r+s)× (2t+19u) =2r× 2t+2r× 19u+s×2t+s×19u =4rt+38ru+2st+19su ⇒ (2r+s)× (2t+19u) nbsp; =4rt+38ru+2st+19su ...

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Standard VII

Mathematics

Multiplication using FOIL Rule

2r+s× 2t+19u=

Question

$(2 r + s) \times (2 t + 19 u) =$

4 r t + 38 r u + 2 s u + 19 s t

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4 r t + 38 r u + 2 s t + 19 s u

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4 r u + 38 r t + 2 s u + 19 s t

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Solution

The correct option is B $4 r t + 38 r u + 2 s t + 19 s u$
Using First Out Inside Last (FOIL) technique,
$\Rightarrow (2 r + s) \times (2 t + 19 u)$
$= 2 r \times 2 t + 2 r \times 19 u + s \times 2 t + s \times 19 u$
$= 4 r t + 38 r u + 2 s t + 19 s u$
$\Rightarrow (2 r + s) \times (2 t + 19 u)$
$= 4 r t + 38 r u + 2 s t + 19 s u$

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(2r+s)×(2t+19u)=

The correct option is B 4rt+38ru+2st+19suUsing First Out Inside Last (FOIL) technique, ⇒(2r+s)×(2t+19u) =2r×2t+2r×19u+s×2t+s×19u =4rt+38ru+2st+19su ⇒(2r+s)×(2t+19u) =4rt+38ru+2st+19su

$(2 r + s) \times (2 t + 19 u) =$