2S2O2-3 aq-I2s- S4O2-6aq-2I-aq S2O2-3aq-2Br2l-5H2Ol- 2SO2-4aq-4Br-aq-10H-aqWhy does the same reductant- thiosulphate react differently with iodine and bromine-

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Potassium Permanganate

2S2O2-3 aq+I2...

Question

$2 S_{2} O_{3}^{2 -} (a q) + I_{2} (s) \to S_{4} O_{6}^{2 -} (a q) + 2 I^{-} (a q)$
$S_{2} O_{3}^{2 -} (a q) + 2 B r_{2} (l) + 5 H_{2} O (l) \to 2 S O_{4}^{2 -} (a q) + 4 B r^{-} (a q) + 10 H^{+} (a q)$
Why does the same reductant, thiosulphate react differently with iodine and bromine?

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2 S_{2} O_{3}^{2 -} (a q) + I_{2} (s) \to S_{4} O_{6}^{2 -} (a q) + 2 I^{-} (a q)

S_{2} O_{3}^{2 -} (a q) + 2 B r_{2} (l) + 5 H_{2} O (l) \to 2 S O_{4}^{2 -} (a q) + 4 B r^{-} (a q) + 10 H^{+} (a q)

Consider the reactions:

(aq) + I₂(s) → (aq) + 2I^–(aq)

aq) + 2Br₂(l) + 5 H₂O(l) → (aq) + 4Br^–(aq) + 10H⁺(aq)

Why does the same reductant, thiosulphate react differently with iodine and bromine?

2 S_{2} O_{3}^{2 -} (a q) + I_{2} (s) ⟶ S_{4} O_{6}^{2 -} (a q) + 2 I^{-} (a q)

S_{2} O_{3}^{2 -} (a q) + 2 {B r}_{2} (l) + 5 H_{2} O (l) ⟶ 2 {S O}_{4}^{2 -} (a q) + 4 {B r}^{-} (a q) + 10 H^{+} (a q)

H^{+}

S_{2} O_{3}^{2 -} (a q) + C r_{2} O_{7}^{2 -} (a q) \to S_{4} O_{6}^{2 -} (a q) + C r^{3 +} (a q)

S_{2} O_{3}^{2 -} (a q) + C r_{2} O_{7}^{2 -} (a q) \to S_{4} O_{6}^{2 -} (a q) + C r^{3 +} (a q)

H^{+}

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