$2 S O_{2_{(} g)} + O_{2_{(} g)} ⇋ 2 S O_{3_{(} g)} + Q k J$
In the above reaction, how can the yield of product be increased without increasing the pressure?

By increasing temperature

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By decreasing temperature

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By increasing the volume of the reaction vessel

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By the addition of the catalyst

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Solution

The correct option is A By decreasing temperature
Since the reaction is exothermic in the forward direction, a decrease in temperature favours the forward reaction.

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Similar questions

2 S O_{2 (g)} + O_{2 (g)} ⇌ 2 S O_{3 (g)}

2 S O_{2} (g) + O_{2} (g) ⇌ 2 S O_{3} (g); △ H^{o} = - 198 k J

The second step in the production of sulphuric acid(contact process) is given by the equation:

$2SO_2 (g) + O_2(g) \rightleftharpoons 2SO_3(g)$

Ideally, which conditions would increase the yield of this reaction?

Consider the following reaction:

$2 S O_{2} (g) + O_{2} (g) ⇋ 2 S O_{3} (g) + h e a t$

If we increase the temperature of the given equilibrium system then an exothermic reaction will be favoured.

How will the rate of reaction $2 S O_{2} (g) + O_{2} (g) \to 2 S O_{3} (g)$ change if the volume of the reaction vessel is halved :

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