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2 SO 2+ O 2->...

Question

2SO2+O2->2SO3 rate of consumption of SO2 is 6.4×10(- 3)kg/Lt/sec calculate the rate of formation of SO3 in kg/Lt/sec?

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Solution

Solution - d[SO2]/dt = 6.410^(-3) , d[SO3]/dt = ?

rate = -1/2 d[SO2]/dt = -d[O2]/dt = 1/2 d[SO3]/dt

given ...d[SO2]/dt = 6.410^(-3)kg/Lt/sec

so -d[SO3]/dt = 1/2 d[SO2]/dt = 1/26.410^(-3) d[SO3]/dt = 3.2*10^(-3)kg/Lt/sec

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