2SO3 (g) ⇌ 2SO2 (g) + O2 (g) ΔH°= +198 kJ
At equilibrium temperature, what shifts the equilibrium to right?
removing sulphur trioxide
adding sulphur trioxide
decreasing the temperature
Fastening decomposition of SO3
4HCl (g) + O2 (g) ⇌ 2H2O (g) + 2Cl2 (g) ΔH° = -114 kJ
What shifts the equilibrium to the left?