2tan3xcos3x-tan3x+1=2cos3x. Find value of x.

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If $tan (3 x + 30) = 1$ then find the value of $x$ .

t a n 3 x = sin 45^{0} cos 45^{0} + sin 30^{0}

x

tan 3 x = sin 45. cos 45 + sin 30

\int \frac{1}{4 {cos}^{3} x - 3 cos x} d x = \frac{1}{k} log (sec 3 x + tan 3 x) .

k

\int_{0}^{π / 2} \frac{cos 3 x + 1}{2 cos x - 1} d x

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