Question

2× ${10}^8$ atoms of carbon are arranged side by side. Calculate the radius of carbon atom if the length of this arrangement is 2.4 cm.

Answer 1

Length of the given arrangement = 2.4 cm
Number of carbon atoms present = 2 × 108
$\therefore$ Diameter of carbon atom
$=\frac{2.4\times {10}^{-2}m}{2\times {10}^8}=1.2\times {10}^{-10}m$
$\therefore$ Radius of carbon atom = $\frac{Diameter}{2}$
=$\frac{1.2\times {10}^{-10}m}{2}=6.0\times {10}^{-11}m$