2× $10^{8}$ atoms of carbon are arranged side by side. Calculate the radius of carbon atom if the length of this arrangement is 2.4 cm.

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Solution

Length of the given arrangement = 2.4 cm
Number of carbon atoms present = 2 × 108
$∴$ Diameter of carbon atom
$= \frac{2.4 \times 10^{- 2} m}{2 \times 10^{8}} = 1.2 \times 10^{- 10} m$
$∴$ Radius of carbon atom = $\frac{D i a m e t e r}{2}$
= $\frac{1.2 \times 10^{- 10} m}{2} = 6.0 \times 10^{- 11} m$

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Atomic Size

Standard XII Chemistry

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2× 108 atoms of carbon are arranged side by side. Calculate the radius of carbon atom if the length of this arrangement is 2.4 cm.

Length of the given arrangement = 2.4 cm Number of carbon atoms present = 2 × 108 ∴ Diameter of carbon atom =2.4×10−2m2×108=1.2×10−10m ∴ Radius of carbon atom = Diameter2 =1.2×10−10m2=6.0×10−11m

2× $10^{8}$ atoms of carbon are arranged side by side. Calculate the radius of carbon atom if the length of this arrangement is 2.4 cm.