2x $^{2}$ + 11x + 14 = 0

4y $^{2}$ + 12y + 9 = 0

(a)

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(b)

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(c)

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(d)

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Solution

The correct option is B
(b)

On solving, We will get

x=- $\frac{7}{2}$ or -2

y=- $\frac{3}{2}$

So, clearly, x $<$ y

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