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Integrating Factor

2 x2+3 x+1=01...

Question

2x $^{2}$ + 3x + 1 = 0

12y $^{2}$ + 7y + 1 = 0

(a)

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(b)

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(c)

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(d)

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(e)

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Solution

The correct option is B
(b)

Here, x = -1 or - $\frac{1}{2}$

& y = - $\frac{1}{3}$ or - $\frac{1}{4}$

So, clearly $x < y$

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2x $^{2}$ + 3x + 1 = 0

12y $^{2}$ + 7y + 1 = 0

α, β

2 x^{2} + 3 x + 1 = 0

\frac{1}{α}, \frac{1}{β}

2 x^{2} + 3 x + 1 = 0

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