$(2 x)^{2} + 4 (2 x) + 7 = M x^{2} + 8 x + 7$ , find value of M

3

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4

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5

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6

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Solution

The correct option is C $4$
L.H.S= $(2 x)^{2} + 4 (2 x) + 7 = 4 x^{2} + 8 x + 7 \neq$ R.H.S
The correct answer is
$(2 x)^{2} + 4 (2 x) + 7 = 4 x^{2} + 8 x + 7$

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Similar questions

Find and correct the errors in the statement: (2x)² + 4(2x) + 7 = 2x² + 8x + 7

(2 x)^{2} + 4 (2 x) + 7 = 2 x^{2} + 8 x + 7

(2 x)^{2} + 4 (2 x) + 7 = 2 x^{2} + 8 x + 7

Which of these statements hold true?

i.) $4 (x - 5) = 4 x - 5$

ii.) $x (3 x + 2) = 3 x^{2} + 2$

iii.) $2 x^{2} + 4 (2 x) + 7 = 2 x^{2} + 8 x + 7$ [4 MARKS]

(2 x)^{2} + 4 (2 x) + 7 = 2 x^{2} + 8 x + 7

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