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Quadratic Formula

2x2+4x-5/2 ÷ ...

Question

( $2 x^{2} + 4 x - \frac{5}{2}) \div (x - \frac{1}{2}$ )

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Solution

Therefore,
$2 x^{2} + 4 x - \frac{5}{2} \div x - \frac{1}{2} = 2 x + 5$
Hence the correct answer is $2 x + 5$ .

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Similar questions

Q. Solve the following inequalities

\frac{x + 1}{x + 5} + \frac{x}{x - 1} < \frac{2 x^{2} + 5 x}{x^{2} + 4 x - 5}

Q. Match the following.

	Column - I		Column - II
(P)	$(x^{2} + 5) (x^{3} + 3) + 5$	(1)	${- x}^{3} - 3 x^{2} + 3 x + 2$
(Q)	$(\frac{- 10}{3} x y^{3}) \times (\frac{6}{5} x^{3} y)$	(2)	$- x^{3} + x^{2} + 3 x - 6$
(R)	$(x^{3} - x^{2} - x - 2) - (2 x^{3} + 2 x^{2} - 4 x - 4)$	(3)	$x^{5} + 5 x^{3} + 3 x^{2} + 20$
(S)	$(x^{3} - x^{2} - x - 2) + (2 x^{2} - 2 x^{3} + 4 x - 4)$	(4)	$- 4 x^{4} y^{4}$

\frac{(x + 1) (4 x - 3) - 4 x^{2} + 5}{4 x + 1}

2

4 x^{2} + 4 x + \frac{3}{2}

2 x^{2} + 3 x + \frac{1}{2}

Q. Find the nature of the roots of the following quadratic equations:
(i)

2 x^{2} - 8 x + 5 = 0

3 x^{2} - 2 \sqrt{6} x + 2 = 0

5 x^{2} - 4 x + 1 = 0

5 x (x - 2) + 6 = 0

12 x^{2} - 4 \sqrt{15} x + 5 = 0

x^{2} - x + 2 = 0

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